# Cutting Length of Triangular Stirrups

The cutting length of the triangular stirrup is done by using Simple and easy formula.

Let’s solve this example for your better understanding.

**EXAMPLE:**

Table of Contents

Suppose we are using a triangular stirrup in a column and a column having a Length 500 mm and having a Width 500 mm (X-section). The clear cover in the column will be 40 mm and the stirrup bar is going to use is 10 mm.

- Calculate the cutting length of the triangular stirrup?
- Also, calculate its weight?

**GIVEN DATA:**

Length of column = 500mm.

Width of column = 500 mm.

Clear cover = 40 mm.

Stirrup bar diameter = 10 mm.

length of the stirrup =?

The weight of the stirrup =?

**SOLUTION:**

The calculation of the triangular stirrup is to be done in 2 steps. In the first step, we calculate the Hypotenuse length of the right angle by using Pythagoras theorem. In the second step, we put these values into our given problem.

**First A is the horizontal x section area and B is vertical x sectional area.**

First we find A:

= 500 – (2 x clear cover) – (2 x half of dia of bar)

= 500 – (2 x 40) – (2 x 5)

= 500 – 80 – 10

= 410mm

Second find B

= (500 – (2 x clear cover) – (2 x half of dia of bar))/2

= (500 – (2 x 40) – (2 x 5))/2

= (500 – 80 – 10)/2

= (410mm)/2

= 205 mm Ans…

Then we find the hypotenuse of the triangle

H=√(base)^{2}+(Perpendicular)^{2}

H=√A^{2}+B^{2}

H=√410^{2}+205^{2}

H = 458.39 mm

**Cutting Length:**

= (2 x H) + 2B + hook – bend

= (2 x H) + 2B + (2 x 10d) – (we have got 4 bends of 135 deg so minus 3d)

(Where d is dia of used in stirrups)

= (2 x H) + 2B + (2 x 10d) – (4 x 3d)

= (2 x 458.39) + 410 + (2 x 10 x 10) – (4 x 3 x 10)

= 916.78 + 410 + 200 – 120

= 1406.7mm or 1.406m

**Weight of this stirrup:**

= d^{2}/162 x length

= 10^{2}/162 x 1.406

= **0.867kg Ans…**

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