# HOW TO CALCULATE THE QUANTITY OF STEEL IN COLUMN (BBS)

## Quantity of steel in Column

The quantity of steel calculation in the column is very easy and simple just needs you little concentration. For your better understanding just look at this example.

**Example:**

suppose we have a column. The height of the column is 4 m and has a cross-sectional area is 300 x 400 mm and a 40 mm clear cover. Six bars are going to use having a diameter of 16 mm. The diameter of the stirrup is 8 mm and has a spacing of 150 mm and @200 mm at L/3 respectively.

**Given Data:**

Height = 4 meter

Cross section = 300 x 400 mm

Clear cover = 40 mm.

No of vertical bars = 6 no’s.

The diameter of the vertical bar = is 16 mm.

Diameter of stirrup = 8 mm.

stirrups center to center spacing = @150 or @ 200 mm.

BBS of Column =?

**Solution:**

The calculation was to proceed in two steps.

- vertical bars calculation
- Cutting length of stirrups

**Step 1:** **Vertical Bar calculation**

Length of 1 bar = H + L_{d}

#Where

L_{d} = development length

h = Height of column

Length of 1 bar

= 4000 mm + 40d <where d is dia of bar>

= 4000 + 40 x 16

= 4000 + 640

= **4640 mm or 4.640 m Ans..**

The length of one vertical bar is 4.640 m. we have a total bar six bars,

Total length

= 6 x 4.640

= **27.84 m long vertical bar is ****required**.

**Step 2: Cutting the length of stirrups in columns**

The cross-sectional area of the column is 300 mm x 400 mm

A is the vertical cross-section area of the stirrup

B is a horizontal cross-section area of the stirrup

** **

**Calculation of length A**

A = Horizontal Distance – 2 Side clear cover

A = 300 – 2 x clear cover

A = 300 – 2 x 40

A = 300 – 80

A = 220 mm

** **

**The length of B**

B = Vertical distance – 2 x Top, Bottom cover

B = 400 – 2 x clear cover

B = 400 – 2 x 40

B = 400 – 80

B = 320 mm

**No of stirrups**

No of stirrups

= 4000/3

=1333.3 mm or 1.33 m

Formula = L/3 / spacing + 1

(no stirrups in the end zone)

=1333.3 / 150

= 8.8 nos say 9 nos

There are a total of two zones of 150 mm spacing and one zone of 200 mm spacing.

= 2 x 9

= 18 nos (at end zones)

At Mid Zone

=1333.3 / 200

= 6.6 nos say 7 nos

Total no of stirrups

= 18 + 7

#### = 25 nos

**Cutting the length of one stirrup**

Formula:

= (2 x A) + (2 x B) + hook – bend

Cutting length

= (2 x A) + (2 x B) + 2 x10d – 5 x 2d

# where

hook = 10d

bend = 5 x 2d (we have 5 bends in one stirrup)

d = is the diameter of the bar

= (2 x 220) + ( 2 x 320) + 2 x 10 x 8 – 2 x 5 x 8

= 440 + 640 + 160 – 80

= **1160 mm or 1.16 m**

We have a total of 25 nos of stirrups, which are going to use,

Total length

= 25 x 1.16

= **29 m long 8 mm bar**.

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**Quantity surveying,** **Concrete, ** **Steel,** and Notes are available in this Android App.

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test

super

Thanks, DHANALAKSHMI