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Quantity of steel in Column
The quantity of steel calculation in the column is very easy and simple just need you little concentration. For your better understanding just look at this example.
suppose we have a column. The height of the column is 4 m and having a cross-sectional area is 300 x 400 mm and having a 40 mm of clear cover. Six bars are going to use having a diameter of 16 mm. The diameter of the stirrup is 8 mm and having a spacing @ 150 mm and @200 mm at L/3 respectively.
Height = 4 meter
Cross section = 300 x 400 mm
Clear cover = 40 mm.
No of vertical bars = 6 no’s.
The diameter of the vertical bar = 16 mm.
Diameter of stirrup = 8 mm.
stirrups center to center spacing = @150 or @ 200 mm.
BBS of Column =?
The calculation was to proceed into two steps.
vertical bars calculation
Cutting length of stirrups
Step 1:Vertical Bar calculation
Length of 1 bar = H + Ld
Ld = development length
h = Height of column
Length of 1 bar
= 4000 mm + 40d <where d is dia of bar>
= 4000 + 40 x 16
= 4000 + 640
= 4640 mm or 4.640 m Ans..
The length one vertical bar is 4.640 m. we have total bar six bars,